There are various transformations that can be applied to a parent trigonometric function in order to change its core attributes. A transformed function can be expressed algebraically as:
\(f(x) = a\sin(k(x-d)) + c\)
- \(a\) represents the vertical stretch/compression factor and the function's amplitude
- \(k\) represents the horizontal stretch/compression factor and affects the function's period and frequency
- \(d\) represents the horizontal shift
- \(c\) represents the vertical shift and the function's axis
Vertical Stretch/Compression
The value of \(a\) will determine whether the transformed function will be vertically stretched or compressed. This also affects the function's amplitude:
- If \(a > 1\), the function will be vertically stretched by a factor of \(a\)
- If \(0 < a < 1\), the function will be compressed by a factor of \(a\)
Horizontal Stretch/Compression
The value of \(k\) will determine whether the transformed function will be horizontally stretched or compressed. This also affects the function's period and frequency:
- If \(0 < k < 1\), the function will be horizontally stretched by a factor of \(1/k\)
- If \(k > 1\), the function will be horizontally compressed by a factor of \(1/k\)
- The period is related to the \(k\) value through the equation \(p = 2\pi/l\)
Horizontal Shift
The value of \(d\) will determine whether the transformed function will be shifted left or right:
- If \(d > 0\), the function will be shifted right
- If \(d < 0\), the function will be shifted left
Vertical Shift
The value of \(c\) will determine whether the transformed function will be shifted upward or downward. This also affects the function's axis:
- If \(c > 0\), the function will be shifted upward
- If \(c < 0\), the function will be shifted downward
Reflections
- If \(a < 0\), the function will either be vertically stretched or compressed with a reflection in the \(x\)-axis
- If \(k < 0\), the function will either be horizontally stretched or compressed with a reflection in the \(y\)-axis
Example
For the function \(f(x) = -3\sin(x - \pi)-1\):
- Identify the parent function
- Identify the transformations that were applied
- Identify the domain and range
- Sketch the transformed function over \(2\) cycles
i. We can identify the parent function as \(\boldsymbol{f(x) = \sin(x)}\).
ii. We can now determine the transformations as such:
- \(\boldsymbol{a = -3}\); vertical stretch by a factor of \(3\) and reflection in the \(x\)-axis
- \(\boldsymbol{d = \pi}\); shifted right by \(\pi\) units
- \(\boldsymbol{c = -1}\); shifted downward \(1\) unit
iii. We can identify the domain and range as such:
- Domain: \(\boldsymbol{\{x\in\mathbb{R}\}}\)
- Range: \(\boldsymbol{\{y\in\mathbb{R} |-4 \leq y \leq 2\}}\)
iv. We can draw our transformed graph as such:
For the function \(g(x) = \cfrac{1}{5}\cos(4x + 2\pi)\):
- Identify the parent function
- Identify the asymptotes
- Identify the domain and range
- Sketch the transformed function over \(2\) cycles
Show Answer
i. We can identify the parent function as \(\boldsymbol{g(x) = \cos(x)}\).
ii. After shifting some of the values in the transformed equation, we can represent it as:
\(g(x) = \cfrac{1}{4}\cos\left[4\left(x + \cfrac{\pi}{2}\right)\right]\)
- \(\boldsymbol{a = 1/5}\); vertical compression by a factor of \(1/5\)
- \(\boldsymbol{k = 4}\); horizontal compression by a factor of \(1/4\)
- \(\boldsymbol{d = -\pi/2}\); shifted left by \(\pi/2\) units
iii. We can identify the domain and range as such:
- Domain: \(\boldsymbol{\{x\in\mathbb{R}\}}\)
- Range: \(\boldsymbol{\{y\in\mathbb{R} |-0.2 \leq y \leq 0.2\}}\)
iv. We can draw our transformed graph as such: