The factored form is when a quadratic function is expressed in the form:
\(y = a(x-p)(x-q)\)
- \(x\) represents the independent variable
- \(y\) represents the dependent variable
- \(a\) represents the compression or stretch factor of the function and determines whether it opens upward or downward
- \(p\) and \(q\) represent the roots or x-intercepts of the function
You can identify the roots of the function when \(y\) is set to \(0\).
Take note that the signs of the x-intercepts are opposite to what they are inside the function.
For example, the x-intercepts of the function \(y = (x-3)(x+5)\) are \(3\) and \(-5\), NOT \(-3\) and \(5\).
A helpful trick is to set \(x\) and the corresponding value to opposite sides. Doing so will change the sign of the value.
Identify the x-intercepts of the function \(y = 2(x + 10)(x + 4)\)
Show Answer
We can identify the arguments as \(x + 10\) and \(x + 4\).
In order to get the x-intercepts, set the values and \(x\) to opposite sides:
\(x = -10\) AND \(x = -4\)
Therefore, we can determine that the x-intercepts of \(y = 2(x + 10)(x + 4)\) are \(-10\) and \(-4\).
Converting Factored Form to Standard Form
- In order to convert to Standard Form, you must first expand the Factored Form through distributive property (also known as the FOIL method)
- Once everything is expanded and all like terms are collected, you must then multiply each term of the result by the value of a
- Finally, rearrange the function if necessary so that the terms appear in descending order
(ie \(x^2 + x + c\))
Convert the quadratic function \(y = 2(x-8)(2x+3)\) from Quadratic Form to Standard Form
Show Answer
First expand the function and collect like terms:
\(y = 2((x)(2x) + (x)(3) + (-8)(2x) + (-8)(3))\)
\(y = 2(2x^2 + 3x - 16x -24)\)
\(y = 2(2x^2 - 13x - 24)\)
Next, multiply each term by \(a\) (in this case, \(2\)):
\(y = 2(2x^2) -2(13x) - 2(24)\)
\(y = 4x^2 -26x - 48\)
Therefore, we can determine that \(2(x-8)(2x+3)\) in Standard Form is \(4x^2 -26x - 48\).
Converting Factored Form to Vertex Form
- Convert to Standard Form following the steps above.
- Then Complete the Square
Graphing Factored Quadratic Functions
The main factors that are useful for sketching a parabola in factored form are:
- x-intercepts
- y-intercept
- vertex
- We can determine the x-intercepts of a function by setting \(x\) and the bracket values to opposite sides as outlined at the start of this lesson
- In order to determine the y-intercept, all we need to do is set \(x = 0\), similar to finding the y-intercept of a linear function. Then, solve by multiplying the remaining values
- In order to determine the vertex, we must first divide the sum of the x-intercepts by \(2\) to determine the x-coordinate of the vertex (also known as the Axis of Symmetry)
- Next, we must place this x-value into the original function which will determine the y-coordinate of the vertex (also known as the Optimal Value)
Example
Identify the x-intercepts, y-intercept and Axis of Symmetry of the factored function \(y = (x - 3)(x + 2)\)
First, we can identify the x-intercepts by placing the \(x\)'s and values on opposite sides:
\(x = 3\) AND \(x = -2\)
Next, we can determine the y-intercept by placing \(0\) as the x-values. Then, solve:
\(y = (0 - 3)(0 + 2)\)
\(y = (-3)(2)\)
\(y = -6\)
Then, we can determine the x-coordinate (or Axis of Symmetry) of the vertex by dividing the sum of the \(x\)-coordinates by \(2\):
\(\text{AOS} = \cfrac{3 - 2}{2}\)
\(\text{AOS} = \cfrac{1}{2}\)
Finally, we can determine the y-coordinate (or Optimal Value) of the vertex by plugging the x-coordinate into the original function:
\(\text{OV} = (\cfrac{1}{2} - 3)(\cfrac{1}{2} + 2)\)
\(\text{OV} = (\cfrac{1}{2} - \cfrac{6}{2})(\cfrac{1}{2} + \cfrac{4}{2})\)
\(\text{OV} = (-\cfrac{5}{2})(\cfrac{5}{2})\)
\(\text{OV} = -\cfrac{25}{4}\)
Therefore, we can determine that the x-intercepts are \(3\) and \(-2\), the y-intercept is \(-6\) and the vertex is (\(\cfrac{1}{2}, -\cfrac{25}{4})\).
Using the following table of values, graph the parabola, determine its x-intercepts, y-intercept and vertex, then determine its factored quadratic function
X |
-4 |
-3 |
-2 |
-1 |
0 |
1 |
2 |
Y
| -10 |
0 |
6 |
8 |
6 |
0 |
-10 |
Show Answer
From the parabola, we can determine that the x-intercepts are \(-3\) and \(1\), the y-intercept is \(6\) and the vertex is (-1, 8).
We can now use the y-intercept to determine the \(a\) value for the factored function:
\(y = a(x-r)(x-s)\)
\(6 = a(0-1)(0+3)\)
\(6 = a(-1)(3)\)
\(6 = -3a\)
\(\cfrac{3a}{3} = -\cfrac{6}{3}\)
\(a = -2\)
We can now use all the known variables to create our final expression:
\(y = -2(x-1)(x+3)\)
Therefore, we can determine that the factored quadratic function is \(-2(x-1)(x+3)\).