Organized counting is a method used in combinatorics to systematically count the number of ways an event can occur. By structuring counting methods logically, we can avoid errors and ensure we consider all possible outcomes. The techniques and mathematical logic for counting possible arrangements or outcomes are useful for a wide variety of applications. Some examples would be a conference manager arranging a schedule of seminars, or a school board trying to make the most efficient use of its buses.
Combinatorics is the branch of mathematics dealing with counting, arranging, and selecting objects. These techniques are useful for probability calculations. One useful tool in combinatorics is a tree diagram, which visually represents all possible outcomes of a situation by branching from one stage to the next.

As you can see here, we have two Main dishes, Chicken or Beef, and each of the two main dishes have two side dishes, Rice or Fries. By using the multiplicative counting principle, we have 4 different possibilities of a meal combination. But, how did we get that number in the first place, and what is the Multiplicative Counting Principle?
By looking at the tree diagram above, we can identify there are 4 possible meal options. There is a systematic way to figure it out, which we will cover in the next section.
The multiplicative counting principle states If a task or process is made up of stages with separate choices:
Where \(m\) is the number of choices for the first stage, \(n\) is the number of choices for the second stage, \(p\) is the number of choices for the third stage, and so on.
Utilizing the following formula:
Where \(m\) is the number of choices for the first stage and \(n\) is the number of choices for the second, we get the following:
\(\text{Outcomes} = 2 * 2\)
\(\text{Outcomes} = 4\)
Therefore, using the Multiplicative Counting Principle, we can determine there are 4 possible meal options.
The indirect counting method is used to count the unwanted cases and subtract from the total possibilities.
We can determine this algebraically as such:
There are 6 possibilities when rolling a dice (1,2,3,4,5,6).
Landing on a 3 only happens when landing on the side of the dice that has the number 3.
We can calculate the number of valid outcomes as such:
\(\text{Valid Outcomes} = 6 - 1\)
\(\text{Valid Outcomes} = 5\)
Therefore, we can determine there are 5 valid outcomes for rolling a number other than 3.