Electromagnetic radiation behaves as both a particle and a wave known as Wave-Particle Duality.
The waves associated the particles are called
The energy of a photon (no rest mass) is given by the following formula:
\(E = hf\)
Where:
NOTE: Planck's constant can be represented as either \(6.626 \cdot 10^{-34} [\text{m}^2 \cdot \text{kg/s}]\) or \(4.136 \cdot 10^{-15} [\text{eVs}]\).
The wavelength is given by the following formula:
\(\lambda = \cfrac{hc}{E}\)
Where:
The momentum is given by the following formula:
\(p = \cfrac{E}{c}\)
Where:
Compute the wavelength of a \(1 \; [\text{MeV}]\) photon.
We can determine the wavelength using the following formula:
\(\lambda = \cfrac{hc}{E}\)
Next, we can substitute the appropriate values and solve:
\(\lambda = \cfrac{(4.136 \cdot 10^{-15} \; [\text{eVs}])(2.9979 \cdot 10^{8} \; [\text{m/s}])}{1*10^6 \; [\text{eV}]} \)
\(\lambda = 1.24 \cdot 10^{-12} \; [\text{m}] \)
Therefore, we can determine the wavelength of the photon is \(\boldsymbol{1.24 \cdot 10^{-12} \; [\textbf{m}]}\).