Solving Polynomial Inequalities by graphing involves using algebraic techniques to determine the intervals where the polynomial is positive or negative and then graphing the solution.
Consider the polynomial inequality \(P(x) = x^3 - 3x^2 - 4x + 12 > 0 \).
Since the polynomial is already written in descending order of degree, we won't need to set things up any further.
In order to identify Critical Points, we can first set the polynomial equal to 0:
Next, we can fully factor the polynomial to determine its roots:
\(P(x) = x^2(x - 3) -4(x -3) = 0\)
\(P(x) = (x^2 -4)(x-3) = 0\)
\(P(x) = (x+2)(x-2)(x-3) = 0\)
Therefore, we can determine the Critical Points as \(x = -2, 2, 3\). These represent the points where \(P(x) = 0\).
We can sketch a graph of the function to illustrate where its greater than \(0\):

Therefore, we can determine that the solution to the inequality \(P(x) > 0\) is \(\boldsymbol{x \in (-\infty, -2) \cup (2, 3)}\).
\(f(x)= x^2 - 10 \lt 3x \)
First, we can move all the terms onto one side and arrange them in descending order of degree:
In order to identify the polynomial's Critical Points, we can set it equal to \(0\):
Next, we can fully factor the polynomial:
We can determine the Critical Points as \(x = -2, 5\).
We can sketch a graph of the function to illustrate where it's less than \(0\):

Therefore, we can determine that the solution to the inequality \(f(x) = x^2 - 10 \lt 3x\) (or \(f(x) = x^2 - 3x - 10 \lt 0\)) is \(\boldsymbol{x \in (-2, 5)}\).
\((x+1)(x-3)^2 \gt 0 \)
Since the polynomial is already fully factored, we won't need to set things up any further.
We can determine the roots as \(x = -1, 3\).
We can sketch a graph of the function to illustrate where its greater than \(0\):

Therefore, we can determine the solution to the inequality \(P(x) \gt 0\) is \(\boldsymbol{x \in (-1, 3) \cup (3, \infty)}\).